The Celsius temperature of a 1.73 L sample of gas is lowered from 80.0°C to 37.0°C. What will be the resulting volume of this gas?

Initial: V₁ = 1.73 L, T₁ = (273.2 + 80.0) K = 353.2 K
Final: V₂ = ? L, T₂ = (273.2 + 37.0) K = 310.2 K

For a fixed amount of gas at constant pressure: V₁/T₁ = V₂/T₂
Resulting volume, V₂ = V₁ × (T₂/T₁) = (1.73 L) × (310.2/353.2) L = 1.52 L