balanced because on the left side this coefficient of 2 means that there is now:
NH4 = 2
SO4 = 1
Na = 2 <--
O=2 <--
H=2 <--
Both coefficients of 2 on the right now mean:
NH3=2<--
Na=2
SO4=1
H=4<--
O=2<--
What am I doing wrong?
Is it anything to do with, NaOH multiplying everything to 2 instead of just the Na?
(NH4)2SO4 + NaOH = NH3 + Na2SO4 + H2O The answer I'm told is: (NH4)2SO4 + 2NaOH = 2NH3 + Na2SO4 + 2H2O I can't understand how this is...?
2017-12-15 1:42 am
回答 (2)
2017-12-15 9:48 am
(NH₄)₂SO₄ and NaOH undergo double decomposition to form Na₂SO₄ and NH₄OH. You can write the balanced equation easily.
(NH₄)₂SO₄ + 2NaOH → Na₂SO₄ + 2[NH₄OH]
NH₄OH cannot stably exist and is thus shown as [NH₄OH]. It will decompose to NH₃ and H₂O, and thus 2[NH₄OH] will decompose to 2NH₃ and 2H₂O.
2[NH₄OH] → 2NH₃ + 2H₂O
Combining the above two equations, the overall equation is :
(NH₄)₂SO₄ + 2NaOH →2NH₃ + Na₂SO₄ + 2H₂O
(NH₄)₂SO₄ + 2NaOH → Na₂SO₄ + 2[NH₄OH]
NH₄OH cannot stably exist and is thus shown as [NH₄OH]. It will decompose to NH₃ and H₂O, and thus 2[NH₄OH] will decompose to 2NH₃ and 2H₂O.
2[NH₄OH] → 2NH₃ + 2H₂O
Combining the above two equations, the overall equation is :
(NH₄)₂SO₄ + 2NaOH →2NH₃ + Na₂SO₄ + 2H₂O
2017-12-15 1:58 am
Of course the 2 multiplies everything: 2Na, 2 O, 2H.
On the left you have:
N = 2
H = 8 + 2 = 10
S = 1
Na = 2
O = 4 + 2 = 6
On the right you have:
N = 2
H = 6 + 4 = 10
Na = 2
S = 1
O = 4 + 2 = 6
On the left you have:
N = 2
H = 8 + 2 = 10
S = 1
Na = 2
O = 4 + 2 = 6
On the right you have:
N = 2
H = 6 + 4 = 10
Na = 2
S = 1
O = 4 + 2 = 6
收錄日期: 2021-04-18 18:00:50
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20171214174214AAYrvEG