maths: logarithmic?

12*9^x=4^x-1
log12+xlog9=(x-1)log4
1.08+0.95x=(x-1)0.6
1.08+0.95x=06x-0.6
0.35x=-1.68
x=-4.8

12 (9ˣ) = 4ˣ ⁻¹
(4*3)(3²ˣ) = 4ˣ ⁻¹
3²ˣ⁺¹ = (4ˣ ⁻¹)/4 - - - - - - - - - - - - - - - -→ 《(aᵐ)(aⁿ) = a⁽ᵐ⁺ⁿ⁾》
3²ˣ⁺¹ = 4ˣ ⁻² - - - - - - - - - - - - - - - - - - -→ 《aᵐ/aⁿ = a⁽ᵐ ⁻ ⁿ⁾》
log (3²ˣ⁺¹) = log (4ˣ ⁻²)
(2x+1) log 3 = (x-2) log 4 - - - - - - - - - - -→《log aˣ = x log a》
2x log 3 - x log 4 = - 2 log 4 - log 3
∴ x = - (2 log 4 + log 3) / (2 log 3 - log 4) = - 4.77 ( to 2 dec. pl.)

12x9^x=4^x-1
4x3x3^2x=4^x-1
3^2x+1=4^x-2
2x+1=(x-2)log4/log3
0.74x=-3.52
x=-4.76