Need Help!!!!!!!!!!!!!?

Let x m be the length of either of the two parts with the same length.
Then, length of the third part = (x + 20) m

The total length of the three parts is 689 m.
(x + 20) + 2x = 689
3x + 20 = 689
3x = 669
x = 223
x + 20 = 243

The lengths of the three parts are 223 m, 223 m and 243 m, respectively.

The let x be the length of the two equal parts. The length of the third side is given as x+20. The three lengths add up to the original length of the fence, so:

x + x + (x+20) = 689
3x + 20 = 689 .... combine like terms
3x = 669 ...... subtract 20 from both sides
x = 223 ..... divide both sides by 3
x+20 = 243

The short parts are 223 m each and the long part is 243 m.

Check: 223 + 223 + 243 = 446 + 243 = 689 .... good.

Length of the fence = 669.
It is so divided that the length of the third part is 20 more that either of the other two.
This brings us to the equation- x + x + (x+10) is 689.
3x + 20 = 689
3x = 689 - 20 (or 669)
1x = 669/3 (or 223)
So the length of the three plots are 223, 223 and 243.

2 parts are 223 m
and
1 part is 243 m.

A fence is 689 m long. It is cut into three parts.
Two parts are the same​ length, and the third part is 20 m longer than either of the other two.
3x + 20 = 689
3x = 669
x = 223
The length of each part:
223 m, 223 m, and 243 m.

Let x be the shorter length.
x + x + x + 20 = 689
3x + 20 = 689
3x = 669
x = 223m
The longer length is 223 + 20 = 243m.

x + x + (x+20) = 689
3x + 20 = 689
x = 223

Two parts are 223 meters each. The third part is 243 meters.

x + x + ( x + 20 ) = 689
3x = 669
x = 223
Parts are 223 m , 223 m and 243 m

X + X + (X+20) = 689
3X = 669
X = 223

Therefore 2 sides are 223 and the other is 243

(X) + (x) + (x + 20) = 689
3x + 20 = 689
3x = 669
X = 223

223, 223, 243

Let the ratio be x:x:(x+20) where the first two parts are x m long.
total = 3x+20

3x+20 = 689
3x = 669
x = 223

The ratio is 223:223:243