what is the spector ions for K2CrO4 + Ba (NO3) 2 - > 2KNO3 + BaCr O4?
回答 (2)
2017-12-08 1:21 pm
The spectator ions are K⁺ and NO₃⁻ ions.
Explanation :
The equation is K₂CrO₄(aq) + Ba(NO₃)₂(aq) → 2KNO₃(aq) + BaCrO₄(s)
On the reactant side, there are 2K⁺, CrO₄²⁻, Ba²⁺ and 2NO₃⁻ ions.
On the product side, there are 2K⁺ , 2NO₃⁻ ions and BaCrO₄ precipitate.
Hence, K⁺ and NO₃⁻ do not react, and thus they are spectator ions.
Explanation :
The equation is K₂CrO₄(aq) + Ba(NO₃)₂(aq) → 2KNO₃(aq) + BaCrO₄(s)
On the reactant side, there are 2K⁺, CrO₄²⁻, Ba²⁺ and 2NO₃⁻ ions.
On the product side, there are 2K⁺ , 2NO₃⁻ ions and BaCrO₄ precipitate.
Hence, K⁺ and NO₃⁻ do not react, and thus they are spectator ions.
2017-12-08 1:11 pm
K{+} and NO3{-}
收錄日期: 2021-04-18 18:03:35
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