F3 Math Question?

draw a line DG parallels to BE and intersect AC on G point
, so DG=BE/2, DG:EF=3:2 ---> EF=(2/3)DG ---> EF=BE/3
the same rule applies, DF=AD/3
triangle ABE=triangle ABD = triangle ABC /2
so triangle AEF = triangle BDF = triangle ABC /6 ......Ans: (A)