What is the pH of an aqueous solution of 2.09×10-3 M hydroiodic acid?
回答 (1)
2017-11-29 3:02 pm
HI (hydroiodic acid) is a strong acid which completely ionized in aqueous solution to give H⁺ ions.
Hence, [H⁺] in the solution = 2.09 × 10⁻³ M
pH = -log[H⁺] = -log(2.09 × 10⁻³) = 2.68
Hence, [H⁺] in the solution = 2.09 × 10⁻³ M
pH = -log[H⁺] = -log(2.09 × 10⁻³) = 2.68
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