Determine the pOH of each solution?
1) [OH−] = 2.5×10−9 M
Classify this solution as acidic, basic, or neutral.
2) [OH−] = 5.0×10−5 M
Classify this solution as acidic, basic, or neutral.
3) [OH−] = 1.0×10−7 M
Classify this solution as acidic, basic, or neutral.
QUESTION 2
Calculate [H3O+] for each solution.
1) pH = 8.55
2) pH = 11.23
3 )pH = 2.17
4) pH = 1.22
CHEMISTRY?
2017-11-21 9:06 pm
回答 (2)
2017-11-21 10:00 pm
1)
pOH = -log[OH⁻] = -log(2.5 × 10⁻⁹) = 8.6
As pOH > 7.0, the solution is acidic.
2)
pOH = -log[OH⁻] = -log(5.0 × 10⁻⁵) = 4.3
As pOH < 7.0, the solution is basic.
3.
pOH = -log[OH⁻] = -log(1.0 × 10⁻⁷) = 7.0
As pOH = 7.0, the solution is neutral.
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QUESTION 2
1)
[H₃O⁺] = 10^(-pH) = 10^(-8.55) M = 2.82 × 10⁻⁹ M
2)
[H₃O⁺] = 10^(-pH) = 10^(-11.23) M = 5.89 × 10⁻¹² M
3)
[H₃O⁺] = 10^(-pH) = 10^(-2.17) M = 6.76 × 10⁻³ M
4)
[H₃O⁺] = 10^(-pH) = 10^(-1.22) M = 6.03 × 10⁻² M
pOH = -log[OH⁻] = -log(2.5 × 10⁻⁹) = 8.6
As pOH > 7.0, the solution is acidic.
2)
pOH = -log[OH⁻] = -log(5.0 × 10⁻⁵) = 4.3
As pOH < 7.0, the solution is basic.
3.
pOH = -log[OH⁻] = -log(1.0 × 10⁻⁷) = 7.0
As pOH = 7.0, the solution is neutral.
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QUESTION 2
1)
[H₃O⁺] = 10^(-pH) = 10^(-8.55) M = 2.82 × 10⁻⁹ M
2)
[H₃O⁺] = 10^(-pH) = 10^(-11.23) M = 5.89 × 10⁻¹² M
3)
[H₃O⁺] = 10^(-pH) = 10^(-2.17) M = 6.76 × 10⁻³ M
4)
[H₃O⁺] = 10^(-pH) = 10^(-1.22) M = 6.03 × 10⁻² M
2017-11-21 9:37 pm
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收錄日期: 2021-04-18 18:06:16
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