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更新1:
WRONG! Heat must be NEGATIVE!
When 5.00 g of solid barium react with chlorine gas to produce solid barium chloride, 31.1 kJ of heat is released.?
2017-11-21 10:59 am
Calculate the heat when 1 mole of barium chloride is produced.
I will rate the Best Answer.
I will rate the Best Answer.
回答 (2)
2017-11-21 11:14 am
The balanced equation for the reaction :
Ba(s) + Cl₂(g) → BaCl₂(g)
Mole ratio Ba : BaCl₂ = 1 : 1
Molar mass of Ba = 137.3 g/mol
No. of moles of 5.00 g Ba = (5.00 g) / (137.3 g/mol) = 0.0364 mol
Heat when 1 mole of Ba reacts = (31.1 kJ) / 0.0364 = 854 kJ
Heat when 1 mole of BaCl₂ is produced = 854 kJ
Ba(s) + Cl₂(g) → BaCl₂(g)
Mole ratio Ba : BaCl₂ = 1 : 1
Molar mass of Ba = 137.3 g/mol
No. of moles of 5.00 g Ba = (5.00 g) / (137.3 g/mol) = 0.0364 mol
Heat when 1 mole of Ba reacts = (31.1 kJ) / 0.0364 = 854 kJ
Heat when 1 mole of BaCl₂ is produced = 854 kJ
2017-11-21 11:10 am
The atomic weight of barium is 137.33.
One mole of barium chloride contains 137.33 grams of barium.
So your answer is (31.1 kJ)*(137.33/5) = 854.2 kJ.
One mole of barium chloride contains 137.33 grams of barium.
So your answer is (31.1 kJ)*(137.33/5) = 854.2 kJ.
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