The density of aluminum is 2.70 g*cm^3. What is the volume and edge length of a cube of Al with a mass of 10.0 g.?
回答 (2)
2017-11-20 1:38 am
Volume of the Al cube
= Mass / Density
= (10.0 g) / (2.70 g/cm³)
= 10.0/2.70 cm³
The edge length of the Al cube
= ∛(Volume of the Al cube)
= ∛(10.0/2.70) cm
= 1.55 cm
= Mass / Density
= (10.0 g) / (2.70 g/cm³)
= 10.0/2.70 cm³
The edge length of the Al cube
= ∛(Volume of the Al cube)
= ∛(10.0/2.70) cm
= 1.55 cm
2017-11-20 1:38 am
density = mass/ volume
Hence
v = m / d
v = 10.0 / 2.70
v = 3.7037037....cm^3 (The volume)
length = 3.7037037... ^(1/3) = 1.547... cm
Hence
v = m / d
v = 10.0 / 2.70
v = 3.7037037....cm^3 (The volume)
length = 3.7037037... ^(1/3) = 1.547... cm
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