Calculate the ionization energy of the lithium dictation, Li2+ using the expression for the energy levels of a one-electron atom: En = -RH Z^2 / n^2, where RH = 2.18 x 10^-18 J.
Please show how you got the answer so that I can use it as an example for similar problems in the future. Thanks.
Calculating Ionization Energy?
2017-11-19 8:35 pm
回答 (1)
2017-11-20 1:46 am
✔ 最佳答案
RH = 2.18 × 10⁻¹⁸ JAtomic number of Li, Z = 3
In ground state, n = 1
En = RH Z² / n² = (2.18 × 10⁻¹⁸ J) × 3² / 1² = 1,96 × 10⁻¹⁷ J
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