Ammonia is produced by the chemical reaction of nitrogen and hydrogen gases.?

a.
N₂(g) + 3H₂(g) → 2NH₃(g)
Mole ratio N₂ : H₂ = 1 : 3

No. of moles of N₂ reacted = 1.0 mol
No. of moles of H₂ needed = (1.0 mol) × 3 = 3.0 mol


b.
N₂(g) + 3H₂(g) → 2NH₃(g)
Mole ratio N₂ : NH₃ = 1 : 2

No. of moles of NH₃ produced = 0.60 mol
No. of moles of N₂ reacted = (0.60 mol) × (1/2) = 0.30 mol


c.
Initial no. of moles of N₂ = Initial no. of moles of H₂ = 1 mol

N₂(g) + 3H₂(g) → 2NH₃(g)
Mole ratio N₂ : H₂ : NH₃ = 1 : 3 : 2

When 1 mole of H₂ completely reacted, N₂ needed = (1 mol) × (1/3) = 0.333 mol < 1 mol
Hence, N₂ is in excess, and thus H₂ is the limiting reactant/reagent (completely reacted).

No. of moles of H₂ reacted = 1 mol
No. of moles of NH₃ produced = (1 mol) × (2/3) = 0.667 mol

Remember that the formula for Ammonia is NH3, meaning that for every N atom, tehre are 3 H atoms. Use that ratio to get your answers.

yes