i need help solving this linear equation? how do i figure out the right coordinates to graph these equations?
2017-11-13 8:31 am
so i have the equations {y-3x=-5{9x-3y=15 i know how to get them in slope intercept form but i want to figure out the right coordinates to graph them and find an intersect (solution) if it exists. at first i used the x coordinates 0,-1,1 but the graph didnt come out right. then i tried 0, -2, 2 but that didnt look right either. what am i doing wrong?
回答 (2)
2017-11-13 9:20 am
9x-3y=15 divided through by -3 is -3x+y=-5 which is y-3x=-5.
These equations define the same line.
For the two intercepts for graphing, y-3x=-5 is x/(5/3)+y/(-5)=1, so the intercepts are 5/3 and -5, at the points (5/3,0) and (0,-5) respectively.
These equations define the same line.
For the two intercepts for graphing, y-3x=-5 is x/(5/3)+y/(-5)=1, so the intercepts are 5/3 and -5, at the points (5/3,0) and (0,-5) respectively.
2017-11-13 8:46 am
9x-3y=15 divided through by -3 is -3x+y=-5 which is y-3x=-5.
These equations define the same line.
For the two intercepts for graphing, y-3x=-5 is x/(5/3)+y/(-5)=1, so the intercepts are 5/3 and -5, at the points (5/3,0) and (0,-5) respectively.
These equations define the same line.
For the two intercepts for graphing, y-3x=-5 is x/(5/3)+y/(-5)=1, so the intercepts are 5/3 and -5, at the points (5/3,0) and (0,-5) respectively.
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