what volume of 0.400 mol/L solution may be prepared from 83.0g of solid KI?
回答 (1)
2017-11-10 4:09 pm
Molar mass of KI = (39.0 + 126.9) g/mol = 165.9 g/mol
No. of moles of KI = (83.0 g) / (165.9 g/mol) = 0.5 mol
Volume = (0.5 mol) / (0.400 mol/L) = 1.25 L
No. of moles of KI = (83.0 g) / (165.9 g/mol) = 0.5 mol
Volume = (0.5 mol) / (0.400 mol/L) = 1.25 L
收錄日期: 2021-04-18 17:55:34
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20171110062537AA0AAgY