Calculate the velocities of electrons with de Broglie wavelengths of 8.3 102 nm and 5.5 nm, respectively.
8.3 x 10^2 nm
m/s
5.5 nm
m/s
Chemistry?
2017-11-10 1:02 pm
回答 (2)
2017-11-10 5:53 pm
Momentum of electron = h/λ = mv
Hence, v = h/(mλ), where
v = Velocity of electron (in m)
h = Planck constant (6.626 × 10⁻³⁴ J s)
m = Mass of electron (9.11 × 10⁻³¹ kg)
λ = Wavelength of electron in wave motion (in m)
When λ = 8.3 × 10² nm :
Velocity of electron = h/(mλ) = (6.626 × 10⁻³⁴) / [(9.11 × 10⁻³¹) × (8.3 × 10² × 10⁻⁹)] = 876 m/s
When λ = 5.5 nm :
Velocity of electron = h/(mλ) = (6.626 × 10⁻³⁴) / [(9.11 × 10⁻³¹) × (5.5 × 10⁻⁹)] = 1.32 × 10⁵ m/s
Hence, v = h/(mλ), where
v = Velocity of electron (in m)
h = Planck constant (6.626 × 10⁻³⁴ J s)
m = Mass of electron (9.11 × 10⁻³¹ kg)
λ = Wavelength of electron in wave motion (in m)
When λ = 8.3 × 10² nm :
Velocity of electron = h/(mλ) = (6.626 × 10⁻³⁴) / [(9.11 × 10⁻³¹) × (8.3 × 10² × 10⁻⁹)] = 876 m/s
When λ = 5.5 nm :
Velocity of electron = h/(mλ) = (6.626 × 10⁻³⁴) / [(9.11 × 10⁻³¹) × (5.5 × 10⁻⁹)] = 1.32 × 10⁵ m/s
2017-11-10 4:07 pm
Use the formula : lambda = h / mv ; lambda : wavelength ; h = Planck ' s constant = 6.626 x 10^-34 kg.m2 / s2 ; m = mass of e- = 9.11 x 10^-31 kg ; v = velocity
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