What is the number of complex zeros for the polynomial function?
f(x)= x^3 - 96x^2 + 400
Algebra Question, please help!?
2017-11-10 9:39 am
回答 (3)
2017-11-10 9:41 am
Since this is a third order function, there are three complex zeros.
2017-11-10 1:15 pm
f(x) = x^3 - 96x^2 + 400
(x - 96) x^2 + 400 = f(x)
Real roots:
x ≈ -2.0201
x ≈ 2.0635
x ≈ 95.957 + 0.×10^-3 i
(x - 96) x^2 + 400 = f(x)
Real roots:
x ≈ -2.0201
x ≈ 2.0635
x ≈ 95.957 + 0.×10^-3 i
2017-11-10 9:59 am
None.
There are three real roots, near -2.02, +2.064, and 95.957.
There are three real roots, near -2.02, +2.064, and 95.957.
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