Algebra Question, please help!?

2017-11-10 9:39 am

What is the number of complex zeros for the polynomial function?

f(x)= x^3 - 96x^2 + 400

回答 (3)

2017-11-10 9:41 am

Since this is a third order function, there are three complex zeros.

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2017-11-10 1:15 pm

f(x) = x^3 - 96x^2 + 400
(x - 96) x^2 + 400 = f(x)
Real roots:
x ≈ -2.0201
x ≈ 2.0635
x ≈ 95.957 + 0.×10^-3 i

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2017-11-10 9:59 am

None.

There are three real roots, near -2.02, +2.064, and 95.957.

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