Mass to mass: Calculate the number of grams of silver chloride produced from 16.4g of silver nitrate. AgNO3+BaCl2->AgCl+Ba(NO3)2. Thanks!?

2017-11-07 2:08 pm

回答 (1)

2017-11-07 11:50 pm
✔ 最佳答案
Molar mass of AgNO₃ = (107.9 + 14.0 + 16.0×3) g/mol = 169.9 g/mol
Molar mass of AgCl = (107.9 + 35.5) g/mol = 143.4 g/mol

2AgNO₃ + BaCl₂ → 2AgCl + Ba(NO₂)₂
Molar ratio AgNO₃ : AgCl = 2 : 2 = 1 : 1

No. of moles of AgNO₃ reacted = (16.4 g) / (169.9 g/mol) = 0.0965 mol
No. of moles of AgCl produced = 0.0965 mol
Mass of AgCl produced = (0.0965 mol) × (143.4 g/mol) = 13.8 g


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