Chemistry question (see details)?
2017-11-07 7:39 am
An electric range burner weighing 624.0 grams is turned off after reaching a temperature of 460.1°C, and is allowed to cool down to 22.4°C. Calculate the specific heat of the burner if all the heat evolved from the burner is used to heat 594.0 grams of water from 22.4°C to 80.3°C.
回答 (1)
2017-11-07 10:02 am
(4.184 J/g·°C) x (594.0 g) x (80.3 - 22.4)°C = 143898.6 J gained by the water (and lost by the burner)
(143898.6 J) / (624.0 g) / (460.1 - 22.4)°C = 0.527 J/g·°C
(143898.6 J) / (624.0 g) / (460.1 - 22.4)°C = 0.527 J/g·°C
收錄日期: 2021-05-01 21:56:59
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