Calculate the mass of 1.23 x 10^24 helium atoms?
回答 (4)
2017-11-06 7:12 pm
1 mole of helium contains 6.02 × 10²³ atoms.
No. of moles of helium = (1.23 × 10²⁴ atoms) / (6.02 × 10²³ atoms/mol) = 2.043 mol
Molar mass of helium = 4.003 g/mol
Mass of helium = (2.043 mol) × (4.003 g/mol) = 8.17 g
No. of moles of helium = (1.23 × 10²⁴ atoms) / (6.02 × 10²³ atoms/mol) = 2.043 mol
Molar mass of helium = 4.003 g/mol
Mass of helium = (2.043 mol) × (4.003 g/mol) = 8.17 g
2017-11-06 6:50 pm
8.17 g He
2017-11-06 6:45 pm
Mass of one He atom = 6.647x10−27 kg from Google or any book.
Required mass = 1.23*6.647*10^-3 kg = 8.18*10^-3 kg or 8.18 g
Required mass = 1.23*6.647*10^-3 kg = 8.18*10^-3 kg or 8.18 g
2017-11-06 9:30 pm
This short video will help you
https://www.youtube.com/watch?v=1q2C5xc_-3Q
https://www.youtube.com/watch?v=1q2C5xc_-3Q
收錄日期: 2021-04-18 17:57:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20171106102829AAqDuO5