A 0.1294 M copper solution has an absorbance of .635. What is the concentration of a copper solution with an absorbance of .291?

First solution : C₁ = 0.1294 M, A₁ = 0.635
Second solution : C₂ = ? M, A₂ = 0.291

Beer's law : C₁/C₂ = A₁/A₂
Then, C₂ = C₁ × (A₂/A₁)

Concentration of the second copper solution, C₂ = (0.1294 M) × (0.291/0.635) = 0.0593 M

A1C2 = A2C1
0.635 x 0.1294 = C2 x 0.291
C2 = 0.282M