What is the temperature of 0.560 mol of gas at a pressure of 1.1 atm and a volume of 12.8 L ?

2017-11-06 3:14 pm
更新1:

Convert each pressure measurement to atm.

回答 (1)

2017-11-06 3:20 pm
Gas law: PV = nRT

Temperature, T = PV/(nR) = (1.1 atm) × (12.8 L) / {(0.560 mol) × [0.0821 atm L / (mol K)]} = 306 K


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