Sample of gas has a mass of 0.545 g. Its volume is 113 mL at a temperature of 75 ∘C and a pressure of 751 mmHgFind the molar mass of the gas?
回答 (1)
2017-11-06 8:25 pm
Consider the sample of gas :
Pressure, P = 751/760 atm
Volume, V = 113/1000 L
Gas constant, R = 0.08206 atm L / (mol K)
Temperature, T = (273 + 75) K = 348 K
Gas law : PV = nRT
No. of moles, n = PV/(RT) = (751/760) × (113/1000) / (0.08206 × 348) mol
Molar mass = (0.545 g) / [(751/760) × (113/1000) / (0.08206 × 348) mol] = 139 g/mol
Pressure, P = 751/760 atm
Volume, V = 113/1000 L
Gas constant, R = 0.08206 atm L / (mol K)
Temperature, T = (273 + 75) K = 348 K
Gas law : PV = nRT
No. of moles, n = PV/(RT) = (751/760) × (113/1000) / (0.08206 × 348) mol
Molar mass = (0.545 g) / [(751/760) × (113/1000) / (0.08206 × 348) mol] = 139 g/mol
收錄日期: 2021-04-18 17:55:54
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