If a combustion reaction of sucrose has a calorie content of 3.87 kcal/gram what is the ∆H? I can't find how to do this anywhere!?
回答 (2)
2017-11-06 8:50 pm
Molar mass of C₁₂H₂₂O₁₁ (sucrose) = (12.0×12 + 1.0×22 + 16.0×11) g/mol = 342.0 g/mol
ΔH of combustion of C₁₂H₂₂O₁₁ = (3.87 kcal/g) × (342 g/mol) = 1320 kcal/mol
ΔH of combustion of C₁₂H₂₂O₁₁ = (3.87 kcal/g) × (342 g/mol) = 1320 kcal/mol
2017-11-06 12:57 pm
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收錄日期: 2021-04-18 17:56:52
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