Oxidation Numbers?
What are the oxidation numbers of the following?
the KMn in KMnO2
the I in HIO2
the Cr2 in K2Cr2O7
回答 (1)
O.N. = oxidation number
KMnO₂ :
O.N. of K = +1
For neutral compound, sum of O.N. = 0
(O.N. of K) + (O.N. of Mn) + (O.N. of O)×2 = 0
(+1) + (O.N. of Mn) + (-2)×2 = 0
O.N. of Mn = +3
====
HIO₂ :
For neutral compound, sum of O.N. = 0
(O.N. of H) + (O.N. of I) + (O.N. of O)×2 = 0
(+1) + (O.N. of I) + (-2)×2 = 0
O.N. of I = +3
====
K₂Cr₂O₇ :
For neutral compound, sum of O.N. = 0
(O.N. of K)×2 + (O.N. of Cr)×2 + (O.N. of O)×7 = 0
(+1)×2 + (O.N. of Cr)×2 + (-2)×7 = 0
(O.N. of Cr)×2 = +12
O.N. of Cr = +6
收錄日期: 2021-04-18 17:58:51
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