求lim x->n [x-[x-0.5]] 可以麻煩寫詳解給我嗎~~ 因為我怎麼算，都覺得左極限跟右極限相等... 非常感謝😁?

Sol
n為整數
lim x->n+_[x－0.5]
=lim x->n_[n+0.001－0.5]
=lim x->n_[n－0.499]
=n－1
lim x->n+_[x－[x－0.5]]
=lim x->n+_[x－(n－1)]
=lim x->n_[n+0.001－n+1]
=lim x->n_[1.001]
=1
lim x->n-_[x－0.5]
lim x->n__[n－0.001－0.5]
=lim x->n_[n－0.051]
=n－1
lim x->n-_[x－[x－0.5]]
=lim x->n-_[x－(n－1)]
=lim x->n_[n－0.001－n+1]
=lim x->n_[0.999]
=0
So
lim x->n__[x－n+2] 不存在