The amount of I3–(aq) in a solution can be determined by titration with a solution containing a known concentration of S2O32–(aq) (thiosulfate ion). The determination is based on the net ionic equation
Given that it requires 26.2 mL of 0.310 M Na2S2O3(aq) to titrate a 25.0-mL sample of I3–(aq), calculate the molarity of I3–(aq) in the solution.
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2017-11-05 3:23 pm
回答 (1)
2017-11-05 4:33 pm
✔ 最佳答案
I₃⁻(aq) + 2S₂O₃²⁻(aq) → 3I⁻(aq) + S₄O₆²⁻(aq)Mole ratio I₃⁻ : S₂O₃²⁻ = 1 : 2
No. of moles of S₂O₃²⁻ reacted = No. of moles of Na₂S₂O₃ reacted = (0.310 mmol/mL) × (26.2 mL) = 8.122 mmol
No. of moles of I₃⁻ = (8.122 mol) × (1/2) = 4.061 mmol
Molarity of I₃⁻ = (4.061 mmol) / (25.0 mL) = 0.162 M
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