What is the molar mass of a 4.10 g sample of gas exerting 1.35 atm of pressure at 325K in a 5.00 L container?
回答 (3)
2017-11-05 4:29 am
✔ 最佳答案
m=4.10 gP = 1.35 atm
T = 325 K
V = 5.00 L
R = 0.082 L atm / K mol
PV = (m/M)RT
M = mRT/PV
M = 4.10 * 0.082 * 325 / (1.35*5.00) = 16.2 g/mol
2017-11-05 4:25 am
Gas law: PV = nRT
n = PV/(RT)
No. of moles of the gas sample, n = 1.35 × 5.00 / (0.0821 × 325) mol
Molar mass of the gas = (4.10 g) / [1.35 × 5.00 / (0.0821 × 325) mol] = 16.2 g/mol
n = PV/(RT)
No. of moles of the gas sample, n = 1.35 × 5.00 / (0.0821 × 325) mol
Molar mass of the gas = (4.10 g) / [1.35 × 5.00 / (0.0821 × 325) mol] = 16.2 g/mol
2017-11-05 4:25 am
PV = nRT
n = PV/RT
n = (1.35 atm)(5.00 L)/(09.0821 Latm/Kmol)(325 K)
n = 0.253 moles
molar mass = 4.10 g/0.253 moles = 16.2 g/mole
n = PV/RT
n = (1.35 atm)(5.00 L)/(09.0821 Latm/Kmol)(325 K)
n = 0.253 moles
molar mass = 4.10 g/0.253 moles = 16.2 g/mole
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