求f(x)=(x^2 -1)^2/3微分後的導數?

👨🏻‍🏫 學術台數學

[匿名]

2017-11-05 1:57 am

回答 (1)

螞蟻雄兵

2017-11-05 6:20 am

Sol
f’(x)=df(x)/dx
=d(x^2－1)^(2/3)/dx
=[d(x^2－1)^(2/3)/d(x^2－1)]*[d(x^2－1)/dx]
=(2/3)*(x^2－1)^(－1/3)*2x
=(4x/3)*(x^2－1)^(－1/3)

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