1 gram of KHP consumed 43.3ml of KOH solution. What is the molarity of KOH?

Molar mass of HC₈H₄O₄K (KHP) = (1.0×5 + 12.0×8 + 16.0×4 + 39.0) g/mol = 204.0 g/mol
(The molar mass learned in lessons should be used instead.)

The equation for the reaction :
HC₈H₄O₄K(aq) + KOH(aq) → C₈H₄O₄K₂(aq) + H₂O(l)
Mole ratio KHP : KOH = 1 : 1

No. of moles of KOH reacted = No. of moles of KHP reacted = (1 g) / (204.0 g/mol)
Molarity of KOH = (1/204.0 mol) / (43.3/1000 L) = 0.113 M