Indicate concentration of each ion present in solution formed by mixing the following. 3.50 g of NaCl in 44.2 mL of 0.238 M CaCl2 solution?

Molar mass of NaCl = (23 + 35.5) g/mol = 58.5 g/mol
No. of moles of NaCl = (3.50 g) / (58.5 g/mol)
Concentration of NaCl = (3.50/58.5 mol) / (44.2/1000 L) = 1.35 M

1 mole of NaCl dissociates in aqueous solution to form 1 mole of Na⁺ ions and 1 mole of Cl⁻ ions.
1 mole of CaCl₂ dissociates in aqueous solution to form 1 mole of Ca²⁺ ions and 2 moles of Cl⁻ ions.

Concentration of Na⁺ ions in the solution = 1.35 M
Concentration of Ca²⁺ ions in the solution = 0.238 M
Concentration of Cl⁻ ions in the solution = (1.35 + 0.238×2) M = 1.83 M (to 3 sig. fig.)