You fire a cannon off a 5 meter tall platform. The cannonball lands 47.7 meters away. What was the cannonball’s horizontal velocity?
回答 (1)
2017-11-06 7:27 am
✔ 最佳答案
Assuming the initial velocity was all horizontal, then the time it took to fall can be found usingh = ½at² (because there is no vertical component):
t = √(2h / a) = √(2 * 5m / 9.8m/s²) = 1.01 s
and so
Vx = d / t = 47.7m / 1.01s = 47.2 m/s ◄
Hope this helps!
收錄日期: 2021-04-24 00:46:25
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