calculus lll?
would you please help me solving this
回答 (1)
Since the numerator and denominator of f are polynomials, it follows that f is continuous whenever its denominator is not equal to 0:
y^2 - x^2 - 1 ≠ 0
==> y^2 - x^2 ≠ 1.
This is all of R^2, except for the hyperbola y^2 - x^2 = 1 (draw with a dashed line), which has its vertices at (0, 1) and (0, -1) and has asymptotes y = x and y = -x.
I hope this helps!
收錄日期: 2021-04-24 00:46:19
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20171101025802AAG2a8T
檢視 Wayback Machine 備份