4KNO3=2K2O+2N2+5O2 (balanced equation)
A: how many moles of KNO3 are available?
B: How many moles of N2 should form?
C: Assuming the gasses are collected under STP, what is the volume of N2 that could be collected?
Chem help! Consider if 65g of KNO3 decomposes according to the following reaction, the molar mass of KNO3 is 101.11 g/mol.?
2017-11-01 10:10 am
回答 (2)
2017-11-01 10:37 am
B)
4KNO₃ → 2K₂O + 2N₂ + 5O₂
Mole ratio KNO₃ : N₂ = 4 : 2 = 2 : 1
No. of moles of N₂ formed = (0.6429 mol) × (1/2) = 0.321 mol
C)
Gas law: PV = nRT
Then, V = nRT/P
Volume of N₂, V = (0.321 mol) × [0.0821 atm L / (mol/K)] × (273 K) / (1 atm) = 7.19 L
4KNO₃ → 2K₂O + 2N₂ + 5O₂
Mole ratio KNO₃ : N₂ = 4 : 2 = 2 : 1
No. of moles of N₂ formed = (0.6429 mol) × (1/2) = 0.321 mol
C)
Gas law: PV = nRT
Then, V = nRT/P
Volume of N₂, V = (0.321 mol) × [0.0821 atm L / (mol/K)] × (273 K) / (1 atm) = 7.19 L
2017-11-01 10:10 am
hjm
收錄日期: 2021-05-01 21:56:20
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