If 856 J of heat was absorbed by a block of iron that weighs 55.0 g, calculate the change in temperature of the block of iron.?
回答 (1)
2017-11-01 9:37 am
Refer to: http://www2.ucdsb.on.ca/tiss/stretton/database/specific_heat_capacity_table.html
Specific heat capacity of iron, c = 0.444 J/g°C
Heat absorbed by the block = m c ΔT
856 J = (55.0 g) × (0.444 J/g°C) × ΔT
Change in temperature, ΔT = 856 / (55.0 × 0.444) °C = 35.1°C
Specific heat capacity of iron, c = 0.444 J/g°C
Heat absorbed by the block = m c ΔT
856 J = (55.0 g) × (0.444 J/g°C) × ΔT
Change in temperature, ΔT = 856 / (55.0 × 0.444) °C = 35.1°C
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