Chemistry hw problem help!?

Rydberg equation :
1/λ = R [(1/n₁²) - (1/n₂²)] …… [1]

and also :
E = hc/λ ……. [2]

Substitute [1] into [2] :
E = h c R [(1/n₁²) - (1/n₂²)]
where,
Energy absorbed, E = 1.61 × 10⁻²¹ J
Planck constant, h = 6.626 × 10⁻³⁴ J s
Speed of light in vacuum, c = 3.00 × 10⁸ m/s
Rydberg constant, R = 1.097 × 10⁷ /m
Initial energy level, n₁ = 6

1.61 × 10⁻²¹ = (6.626 × 10⁻³⁴) × (3.00 × 10⁸) × (1.097 × 10⁷) × [(1/6²) - (1/n₂²)]
(1/36) - (1/n₂²) = 7.38 × 10⁻⁴
1/n₂² = 0.0270
n₂² = 37.0
n₂ ≈ 6
This is impossible.

But if the energy absorbed is 16.1 × 10⁻²¹ J = 1.61 × 10⁻²⁰ J instead, then
1.61 × 10⁻²⁰ = (6.626 × 10⁻³⁴) × (3.00 × 10⁸) × (1.097 × 10⁷) × [(1/6²) - (1/n₂²)]
(1/36) - (1/n₂²) = 7.38 × 10⁻³
1/n₂² = 0.0204
n₂² = 49.0
n₂ = 7

Hence, it is excited to n = 7

you keep asking these Rydberg related questions. I've shown you how to work them out several times.
https://answers.yahoo.com/question/index?qid=20171031130117AAd0zKW
https://answers.yahoo.com/question/index?qid=20171030225327AADKfuZ

This time, if you want further help... show your work. YOU need to work these problems out and learn the material.