Work done question. No idea?
Calculate the energy transferred by a force of 12N when it moves an object by a distance of 4.0 m
a) in the direction of the force
b) in a direction at 60 degrees to the direction of the force
c) in a direction at right angles to the direction of the force?
What the hell?
回答 (3)
a)
Force in the direction of the motion = 12 N
Energy transferred (Work done) = F s = 12 × 4.0 J = 48 J
====
b)
Force in the direction of motion = (12 N) × cos60° = 6 N
Energy transferred (Work done) = F s = 6 × 4.0 J = 24 J
====
c)
Force in the direction of motion = (12 N) × cos90° = 0
Energy transferred (Work done) = F s = 0 × 4.0 J = 0 J
Always net force in the direction. F(net vector) times d's vector. It's that simple. It's only complicated if the force or direction changes. like a roller coaster, for example.
With a constant force and constant direction of motion, W = F d cos(θ)
More generally, W = ∫ F • dx
• means the vector dot product. A • B is the magnitude of A times the component of B in the direction of A. (Or vice versa; it's commutative.)
The confusing part is that the question implies this force causes the object's motion. There must be other forces and/or momentum involved. This is how much work is done by gravity when an object (a) falls straight down, (b) slides down a 30° incline, or (c) is in a circular orbit.
收錄日期: 2021-04-18 17:55:24
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20171031082742AAfc59k
檢視 Wayback Machine 備份