If the flask volume is 4.50 L, and the air is at standard temperature and pressure, how many gaseous molecules does the flask contain?
回答 (1)
2017-10-30 4:11 pm
At standard temperature and pressure, 1 mole of gas occupies a volume of 22.4 L and have 6.02 × 10²³ molecules.
No. of gaseous molecules = (4.50 L) × (1 mol / 22.4 L) × (6.02 × 10²³ molecules/mol) = 1.21 × 10 ²³ molecules
No. of gaseous molecules = (4.50 L) × (1 mol / 22.4 L) × (6.02 × 10²³ molecules/mol) = 1.21 × 10 ²³ molecules
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