A gaseous mixture contains 411.0 Torr of H2(g),382.1 Torr of N2(g), & 67.5 Torr of Ag(g). What will be the mole fraction of Xh2, XN2, XAr?
回答 (1)
2017-10-30 8:55 am
Total pressure, P(T) = (411.0 + 382.1 + 67.5) torr = 860.6 torr
Mole fraction of H₂, X(H₂) = p(H₂)/P(T) = 411.0/860.6 = 0.4776
Mole fraction of N₂, X(N₂) = p(N₂)/P(T) = 382.1/860.6 = 0.4440
Mole fraction of Ne, X(Ne) = p(Ne)/P(T) = 67.5/860.6 = 0.0784
Mole fraction of H₂, X(H₂) = p(H₂)/P(T) = 411.0/860.6 = 0.4776
Mole fraction of N₂, X(N₂) = p(N₂)/P(T) = 382.1/860.6 = 0.4440
Mole fraction of Ne, X(Ne) = p(Ne)/P(T) = 67.5/860.6 = 0.0784
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