What is the final concentration of 18.1 mL iron(III) chloride sol with an intl conc of 1.89M which is diluted with 15.7mL of solvent?

Initial : M₁ = 1.89 M, V₁ = 18.1 mL
Final : M₂ = ?, V₂ = (18.1 + 15.7) mL = 33.8 mL

M₁ V₁ = M₂ V₂
(1.89 M) × (18.1 mL) = M₂ × (33.8 mL)
Final concentration, M₂ = 1.89 × 18.1 / 33.8 M = 1.01 M