✔ 最佳答案
The equation for the production of CO should be "2 C(s) + O₂(g) → 2 CO(g)" instead.
Molar mass of C = 12.0 g/mol
Molar mass of CO = (12.0 + 16.0) g/mol = 28.0 g/mol
Molar mass of CO₂ = (12.0 + 16.0×2) g/mol = 44.0 g/mol
Consider the production of CO :
2 C(s) + O₂(g) → 2 CO(g)
Mole ratio C : CO = 2 : 2 = 1 : 1
Mass of C consumed = (400 g) / 2 = 200 g
No. of moles of C consumed = (200 g) / (12 g/ mol) = 16.67 mol
No. of moles of CO produced = 16.67 mol
Mass of CO produced = (16.67 mol) × (28 g/mol) = 466.76 g
Consider the production of CO₂ :
C(s) + O₂(g) → CO₂(g)
Mole ratio C : CO₂ = 1 : 1
Mass of C consumed = (400 g) / 2 = 200 g
No. of moles of C consumed = (200 g) / (12 g/ mol) = 16.67 mol
No. of moles of CO₂ produced = 16.67 mol
Mass of CO₂ produced = (16.67 mol) × (44 g/mol) = 733.48 g
Total mass of gas produced = (466.76 + 733.48) g = 1200.24 g ≈ 1200 g