Cu + 4HNO3 = Cu(NO3)2 + 2NO2 + 2H2O
I think the oxidation would be
Cu = Cu(+2) + 2e-
But I'm not sure what the reduction would be?
收錄日期: 2021-04-18 18:11:30
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20171029163014AAYpwcs