Chemistry Problem?
1) You have an unknown cation (one of the ten from this experiment). Your solution is colorless and odorless. Treatment with HCl produces no observable change. Treatment with NaOH produces a white gelatinous precipitate that dissolves in excess NH3. Treatment with NaOH also produces a white gelatinous precipitate which dissolves in excess NaOH. What is the identity of your cation?
2) Write net ionic equations for the reactions as described in Question #1. (Note: You should have four equations)
回答 (1)
1)
It is zinc ion, Zn²⁺ ion.
This is because zinc ion does not react with HCl. Zinc ion reacts with NH₃ to form white gelatinous precipitate of Zn(OH)₂, which dissolves in excess NH₃. Zinc ion also reacts with NaOH to form a white gelatinous precipitate of Zn(OH)₂, which dissolves in excess NaOH.
2.
Zinc ion reacts with NH₃ to form white gelatinous precipitate of Zn(OH)₂, which dissolves in excess NH₃.
NH₃(aq) + H₂O(l) ⇌ NH₄⁺(aq) + OH⁻(aq)
Zn²⁺(aq) + 2OH⁻(aq) → Zn(OH)₂(s)
Zn(OH)₂(s) + 4NH₃(aq) → [Zn(NH₃)₄]²⁺(aq) + 2OH⁻(aq)
Zinc ion also reacts with NaOH to form a white gelatinous precipitate of Zn(OH)₂, which dissolves in excess NaOH.
Zn²⁺(aq) + 2OH⁻(aq) → Zn(OH)₂(s)
Zn(OH)₂(s) + 2OH⁻(aq) → [Zn(OH)₄]²⁻(aq)
收錄日期: 2021-04-24 00:50:31
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