What is the molar mass, in g mol^1, of MgSO4x7H2O (please explain steps)?

The chemical formula of the compound should be MgSO₄•7H₂O.
(If you write "x" instead of "•", someone will be misled to perform multiplication."

Molar masses to one decimal place :
Mg = 24.3 g/mol
S = 32.1 g/mol
O = 16.00 g/mol
H = 1.0 g/mol

Molar mass of MgSO₄ = (24.3 + 32.1 + 16.0×4) g/mol = 120.4 g/mol
Molar mass of H₂O = (1.0× 2 + 16.0) g/mol = 18.0 g/mol

Hence, molar mass of MgSO₄•7H₂O = (120.4 + 18.0×7) g/mol = 246.4 g/mol

M(MgSO₄)
=24+32+(16)4
=120 g/mol

M(H₂O)
=(1)2+16
=18 g/mol
as there is 7 mol of water
so, 18 x 7 = 126 g/mol

M(MgSO₄) x M(H₂O)
=120 x 126
=15120 g/mol


**M=R.M.M=molar mass

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