Chemistry question?
2017-10-26 1:24 am
you measure out 11 mLs of acetic anhydride by mistake. If you are given a density of 1.08 g/mL and a molecular weight of 102.09 g/mol, how many mols of acetic anhydride did you use in your reaction?
回答 (1)
2017-10-26 1:40 am
No. of moles of acetic anhydride
= (11 mL) × (1.08 g/mL) / (102.09 g/mol)
= 0.116 mol
= (11 mL) × (1.08 g/mL) / (102.09 g/mol)
= 0.116 mol
收錄日期: 2021-04-18 17:57:22
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