How many moles of Sodium are there in 110 grams of NaHCO3?

Molar mass of NaHCO₃ = (23.0 + 1.0 + 12.0 + 16.0×3) g/mol = 84.0 g/mol

No. of moles of NaHCO₃ = (110 g) / (84.0 g/mol) = 1.31 mol