What is the mass (in grams) of 7.14 x 10^23 molecules of C6H12O6?
回答 (2)
2017-10-25 10:13 am
Avogadro constant = 6.02 × 10²³ /mol
No. of moles of C₆H₁₂O₆ = (7.14 × 10²³ ) / (6.02 × 10²³ /mol) = 7.14/6.02 mol
Molar mass of C₆H₁₂O₆ = (12.0×6 + 1.0×12 + 16.0×6) g/mol = 180.0 g/mol
Mass of C₆H₁₂O₆ = (7.14/6.02 mol) × (180.0 g/mol) = 213 g
No. of moles of C₆H₁₂O₆ = (7.14 × 10²³ ) / (6.02 × 10²³ /mol) = 7.14/6.02 mol
Molar mass of C₆H₁₂O₆ = (12.0×6 + 1.0×12 + 16.0×6) g/mol = 180.0 g/mol
Mass of C₆H₁₂O₆ = (7.14/6.02 mol) × (180.0 g/mol) = 213 g
2017-10-25 10:35 am
This is glucose. Let’s determine the mass of mole.
Mass = 6 * 12 + 12 * 1 + 6 * 16 = 180 grams
One mole is 6.02 * 10^23 molecules.
Number of moles = 7.14 ÷ 6.02
This is approximately 1.19 moles.
Mass = 180 * 7.14 ÷ 6.02
This is approximately 213 grams. I hope this is helpful for you.
Mass = 6 * 12 + 12 * 1 + 6 * 16 = 180 grams
One mole is 6.02 * 10^23 molecules.
Number of moles = 7.14 ÷ 6.02
This is approximately 1.19 moles.
Mass = 180 * 7.14 ÷ 6.02
This is approximately 213 grams. I hope this is helpful for you.
收錄日期: 2021-04-24 00:47:45
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