When 6.58 grams of NH4Cl is dissolved in 100g of water, how many moles of cation are produced?
回答 (2)
2017-10-24 9:45 am
The mass of water is redundant.
Molar mass of NH₄Cl = (14.0 + 1.0×4 + 35.5) g/mol = 53.5 g/mol
No. of moles of NH₄Cl = (6.58 g) / (53.5 g/mol) = 0.123 mol
1 mole of NH₄Cl dissociates to give 1 mole of NH₄⁺ cations.
No. of moles of NH₄⁺ produced = 0.123 mol
Molar mass of NH₄Cl = (14.0 + 1.0×4 + 35.5) g/mol = 53.5 g/mol
No. of moles of NH₄Cl = (6.58 g) / (53.5 g/mol) = 0.123 mol
1 mole of NH₄Cl dissociates to give 1 mole of NH₄⁺ cations.
No. of moles of NH₄⁺ produced = 0.123 mol
2017-10-24 9:46 am
NH4(+) is the cation
18+35.5 = 53.5
6.58 / 53.5 << use a calculator
18+35.5 = 53.5
6.58 / 53.5 << use a calculator
收錄日期: 2021-04-18 17:58:09
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