For the following reaction, 0.546 moles of carbon (graphite) are mixed with 0.255 moles of oxygen gas.
Carbon+Oxygen=Carbon dioxide
What is the formula for the limiting reagent?
What is the maximum amount of carbon dioxide that can be produced?
Chemistry Help!?
2017-10-24 9:26 am
回答 (2)
2017-10-24 10:06 am
Equation for the reaction :
C + O₂ → CO₂
Mole ratio C : O₂ = 1 : 1
Since (Initial number of moles of C) = 0.546 mol > 0.255 mol = (Initial number of O₂)
then C is in excess, and O₂ completely reacts.
Formula of the limiting reagent = O₂
According to the above equation, mole ratio O₂ : CO₂ = 1 : 1
Maximum no. of moles of CO₂ produced = No. of moles of O₂ reacted = 0.255 mol
Molar mass of CO₂ = (12.0 + 16.0×2) = 44.0 g/mol
Maximum mass of CO₂ = (0.255 mol) × (44.0 g/mol) = 11.2 g (to 3 sig. fig.)
C + O₂ → CO₂
Mole ratio C : O₂ = 1 : 1
Since (Initial number of moles of C) = 0.546 mol > 0.255 mol = (Initial number of O₂)
then C is in excess, and O₂ completely reacts.
Formula of the limiting reagent = O₂
According to the above equation, mole ratio O₂ : CO₂ = 1 : 1
Maximum no. of moles of CO₂ produced = No. of moles of O₂ reacted = 0.255 mol
Molar mass of CO₂ = (12.0 + 16.0×2) = 44.0 g/mol
Maximum mass of CO₂ = (0.255 mol) × (44.0 g/mol) = 11.2 g (to 3 sig. fig.)
2017-10-24 9:49 am
O2 is the lim. reactant
0.255 / 2 = moles of CO2 produced ... just divide
0.255 / 2 = moles of CO2 produced ... just divide
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