In XeF4O2, what would the F-Xe-F, F-Xe-O and O-Xe-O bond angles be? Are bond angles always 90 degrees in an octahedral molecular shape?

Bond angles :
∠F-Xe-F = ∠ F-Xe-O = 90°
∠O-Xe-O = 180°

For an regular octahedral molecular shape, the bond angle is always 90° or 180° .
If the shape is distorted, the bond angle varies slightly from 90°.