Chemistry, please help! I keep getting the wrong answer! Due at midnight?
A mixture of 38.4 g of Cr(NO3)2 and 60.8 g of CuSO4 is dissolved in sufficient water to make 245 mL of solution, where the cations react. In the reaction, copper metal is formed and each chromium ion loses one electron.What is the molar concentration of SO2− an- 4
ions in the solution? Answer in units of M.
回答 (2)
The net ionic equation for the reaction :
2Cr²⁺(aq) + Cu²⁺(aq) → 2Cr³⁺(aq) + Cu(s)
SO₄²⁻ ions do not take place in the reaction.
Therefore, the concentration of SO₄²⁻ ions is unchanged during the reaction.
Molar mass of CuSO₄ = (63.5 + 32.1 + 16.0×4) g/mol = 159.6 g/mol
Initial no. of moles of CuSO₄ = (60.8 g) / (159.6 g/mol) = 0.381 mol
1 mole of CuSO₄ dissociates to give 1 mole of SO₄²⁻ ions.
No. of moles of SO₄²⁻ ions in the solution = Initial no. of moles of CuSO₄ = 0.381 mol
Volume of the solution = 245 mL = 0.245 L
Molar concentration of SO₄²⁻ ions in the solution = (0.381 mol) / (0.245 L) = 1.56 M
2 Cr(NO3)2 + CuSO4 → Cu + 2 Cr{3+} + 4 NO3{-} + SO4{2-}
The reaction described is entirely bogus -- it doesn't happen like that.
However the question can still be answered because the SO4{2-} ions don't participate in the supposed reaction anyway -- they are spectator ions.
(60.8 g CuSO4) / (159.6086 g CuSO4/mol) x (1 mol SO4{2-} / 1 mol CuSO4) / (0.245 L) =
1.55 mol/L SO4{2-} = 1.55 M SO4{2-}
收錄日期: 2021-04-18 18:05:08
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